4x/x^2-9-4/x-3

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Solution for 4x/x^2-9-4/x-3 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*x)/(x^2)-(4/x)-9-3 = 0

(4*x)/(x^2)-4*x^-1-9-3 = 0

-12 = 0

x belongs to the empty set

x belongs to the empty set

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